Distance from Montgomery County to Banovo Polje
The distance between Montgomery County, United States and Banovo Polje, Serbia is 8,629 km (5,362 miles) in a straight line. If a road route exists, expect roughly 10786 km (6702 miles) by car — around 134 h 49 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 8,629 km / 5,362 mi |
| Road distance (estimate) | ≈ 10786 km / 6702 mi |
| Driving time (estimate) | ≈ 134 h 49 min |
| Flight time (estimate) | ≈ 10 h 39 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Montgomery County, United States | 32.220250989863 | -86.207638817186 |
| Banovo Polje, Serbia | 44.9092485 | 19.4461467 |
Frequently asked questions
How far is Banovo Polje from Montgomery County?
The straight-line (air) distance from Montgomery County, United States to Banovo Polje, Serbia is 8,629 km (5,362 miles). By road it is roughly 10786 km (6702 miles), depending on the route.
How long does it take to drive from Montgomery County to Banovo Polje?
Approximately 134 h 49 min, assuming an 80 km/h average over an estimated road distance of 10786 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Montgomery County to Banovo Polje?
A direct flight covers 8,629 km in about 10 h 39 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Banovo Polje to Montgomery County (reverse route)
GPS coordinates of Montgomery County GPS coordinates of Banovo Polje