Distance from Montgomery to Banovo Polje
The distance between Montgomery, United States and Banovo Polje, Serbia is 8,622 km (5,358 miles) in a straight line. If a road route exists, expect roughly 10778 km (6697 miles) by car — around 134 h 43 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 8,622 km / 5,358 mi |
| Road distance (estimate) | ≈ 10778 km / 6697 mi |
| Driving time (estimate) | ≈ 134 h 43 min |
| Flight time (estimate) | ≈ 10 h 39 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Montgomery, United States | 32.376542 | -86.2996608 |
| Banovo Polje, Serbia | 44.9092485 | 19.4461467 |
Frequently asked questions
How far is Banovo Polje from Montgomery?
The straight-line (air) distance from Montgomery, United States to Banovo Polje, Serbia is 8,622 km (5,358 miles). By road it is roughly 10778 km (6697 miles), depending on the route.
How long does it take to drive from Montgomery to Banovo Polje?
Approximately 134 h 43 min, assuming an 80 km/h average over an estimated road distance of 10778 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Montgomery to Banovo Polje?
A direct flight covers 8,622 km in about 10 h 39 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Banovo Polje to Montgomery (reverse route)
GPS coordinates of Montgomery GPS coordinates of Banovo Polje