Distance from Banovo Polje to Montgomery County
The distance between Banovo Polje, Serbia and Montgomery County, United States is 8,629 km (5,362 miles) in a straight line. If a road route exists, expect roughly 10786 km (6702 miles) by car — around 134 h 49 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 8,629 km / 5,362 mi |
| Road distance (estimate) | ≈ 10786 km / 6702 mi |
| Driving time (estimate) | ≈ 134 h 49 min |
| Flight time (estimate) | ≈ 10 h 39 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Banovo Polje, Serbia | 44.9092485 | 19.4461467 |
| Montgomery County, United States | 32.220250989863 | -86.207638817186 |
Frequently asked questions
How far is Montgomery County from Banovo Polje?
The straight-line (air) distance from Banovo Polje, Serbia to Montgomery County, United States is 8,629 km (5,362 miles). By road it is roughly 10786 km (6702 miles), depending on the route.
How long does it take to drive from Banovo Polje to Montgomery County?
Approximately 134 h 49 min, assuming an 80 km/h average over an estimated road distance of 10786 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Banovo Polje to Montgomery County?
A direct flight covers 8,629 km in about 10 h 39 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Montgomery County to Banovo Polje (reverse route)
GPS coordinates of Banovo Polje GPS coordinates of Montgomery County