Distance from Seymour to Aragon
The distance between Seymour, United States and Aragon, United States is 551 km (343 miles) in a straight line. If a road route exists, expect roughly 689 km (428 miles) by car — around 8 h 37 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 551 km / 343 mi |
| Road distance (estimate) | ≈ 689 km / 428 mi |
| Driving time (estimate) | ≈ 8 h 37 min |
| Flight time (estimate) | ≈ 1 h 9 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Seymour, United States | 38.957531 | -85.885428 |
| Aragon, United States | 34.044708 | -85.060974 |
Frequently asked questions
How far is Aragon from Seymour?
The straight-line (air) distance from Seymour, United States to Aragon, United States is 551 km (343 miles). By road it is roughly 689 km (428 miles), depending on the route.
How long does it take to drive from Seymour to Aragon?
Approximately 8 h 37 min, assuming an 80 km/h average over an estimated road distance of 689 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Seymour to Aragon?
A direct flight covers 551 km in about 1 h 9 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Aragon to Seymour (reverse route)
GPS coordinates of Seymour GPS coordinates of Aragon