Seymour: latitude and longitude
Seymour, Connecticut, United States is at latitude 38.957531 and longitude -85.885428.
Latitude38.957531
Longitude-85.885428
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<iframe src="https://geloky.com/geocoding/embed/Seymour+United+States" width="100%" height="350" style="border:0" loading="lazy" title="Map of Seymour United States"></iframe> <p>Map of <a href="https://geloky.com/geocoding/place/Seymour+United+States">Seymour United States GPS coordinates</a> by Geloky</p>
FAQ
Questions about Seymour
The latitude of Seymour is 38.957531 and the longitude is -85.885428. In degrees, minutes and seconds: 38°57'27.11"N 85°53'7.54"W.
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