Distance from Loxley to San Felipe
The distance between Loxley, United States and San Felipe, Chile is 7,271 km (4,518 miles) in a straight line. If a road route exists, expect roughly 9089 km (5648 miles) by car — around 113 h 37 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 7,271 km / 4,518 mi |
| Road distance (estimate) | ≈ 9089 km / 5648 mi |
| Driving time (estimate) | ≈ 113 h 37 min |
| Flight time (estimate) | ≈ 9 h 3 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Loxley, United States | 30.62206 | -87.752994 |
| San Felipe, Chile | -32.7505012 | -70.7237173 |
Frequently asked questions
How far is San Felipe from Loxley?
The straight-line (air) distance from Loxley, United States to San Felipe, Chile is 7,271 km (4,518 miles). By road it is roughly 9089 km (5648 miles), depending on the route.
How long does it take to drive from Loxley to San Felipe?
Approximately 113 h 37 min, assuming an 80 km/h average over an estimated road distance of 9089 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Loxley to San Felipe?
A direct flight covers 7,271 km in about 9 h 3 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from San Felipe to Loxley (reverse route)
GPS coordinates of Loxley GPS coordinates of San Felipe