Distance from Loxley to San Antonio Province
The distance between Loxley, United States and San Antonio Province, Chile is 7,341 km (4,561 miles) in a straight line. If a road route exists, expect roughly 9176 km (5702 miles) by car — around 114 h 42 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 7,341 km / 4,561 mi |
| Road distance (estimate) | ≈ 9176 km / 5702 mi |
| Driving time (estimate) | ≈ 114 h 42 min |
| Flight time (estimate) | ≈ 9 h 8 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Loxley, United States | 30.62206 | -87.752994 |
| San Antonio Province, Chile | -33.58333 | -71.5 |
Frequently asked questions
How far is San Antonio Province from Loxley?
The straight-line (air) distance from Loxley, United States to San Antonio Province, Chile is 7,341 km (4,561 miles). By road it is roughly 9176 km (5702 miles), depending on the route.
How long does it take to drive from Loxley to San Antonio Province?
Approximately 114 h 42 min, assuming an 80 km/h average over an estimated road distance of 9176 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Loxley to San Antonio Province?
A direct flight covers 7,341 km in about 9 h 8 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from San Antonio Province to Loxley (reverse route)
GPS coordinates of Loxley GPS coordinates of San Antonio Province