Distance from Chinautla to Seymour
The distance between Chinautla, Guatemala and Seymour, United States is 2,735 km (1,699 miles) in a straight line. If a road route exists, expect roughly 3418 km (2124 miles) by car — around 42 h 44 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 2,735 km / 1,699 mi |
| Road distance (estimate) | ≈ 3418 km / 2124 mi |
| Driving time (estimate) | ≈ 42 h 44 min |
| Flight time (estimate) | ≈ 3 h 43 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Chinautla, Guatemala | 14.700991359 | -90.501399157 |
| Seymour, United States | 38.957531 | -85.885428 |
Frequently asked questions
How far is Seymour from Chinautla?
The straight-line (air) distance from Chinautla, Guatemala to Seymour, United States is 2,735 km (1,699 miles). By road it is roughly 3418 km (2124 miles), depending on the route.
How long does it take to drive from Chinautla to Seymour?
Approximately 42 h 44 min, assuming an 80 km/h average over an estimated road distance of 3418 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Chinautla to Seymour?
A direct flight covers 2,735 km in about 3 h 43 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Seymour to Chinautla (reverse route)
GPS coordinates of Chinautla GPS coordinates of Seymour