Distance from Waterbury to Mianay
The distance between Waterbury, United States and Mianay, Philippines is 13,904 km (8,639 miles) in a straight line. If a road route exists, expect roughly 17379 km (10799 miles) by car — around 217 h 14 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 13,904 km / 8,639 mi |
| Road distance (estimate) | ≈ 17379 km / 10799 mi |
| Driving time (estimate) | ≈ 217 h 14 min |
| Flight time (estimate) | ≈ 16 h 51 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Waterbury, United States | 41.5542609 | -73.0430692 |
| Mianay, Philippines | 11.4613732 | 122.691703 |
Frequently asked questions
How far is Mianay from Waterbury?
The straight-line (air) distance from Waterbury, United States to Mianay, Philippines is 13,904 km (8,639 miles). By road it is roughly 17379 km (10799 miles), depending on the route.
How long does it take to drive from Waterbury to Mianay?
Approximately 217 h 14 min, assuming an 80 km/h average over an estimated road distance of 17379 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Waterbury to Mianay?
A direct flight covers 13,904 km in about 16 h 51 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Mianay to Waterbury (reverse route)
GPS coordinates of Waterbury GPS coordinates of Mianay