Distance from Villa de San Antonio to Oxford
The distance between Villa de San Antonio, Honduras and Oxford, United States is 2,241 km (1,392 miles) in a straight line. If a road route exists, expect roughly 2801 km (1740 miles) by car — around 35 h 1 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 2,241 km / 1,392 mi |
| Road distance (estimate) | ≈ 2801 km / 1740 mi |
| Driving time (estimate) | ≈ 35 h 1 min |
| Flight time (estimate) | ≈ 3 h 8 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Villa de San Antonio, Honduras | 14.292823407956 | -87.538110139108 |
| Oxford, United States | 34.3668 | -89.518625 |
Frequently asked questions
How far is Oxford from Villa de San Antonio?
The straight-line (air) distance from Villa de San Antonio, Honduras to Oxford, United States is 2,241 km (1,392 miles). By road it is roughly 2801 km (1740 miles), depending on the route.
How long does it take to drive from Villa de San Antonio to Oxford?
Approximately 35 h 1 min, assuming an 80 km/h average over an estimated road distance of 2801 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Villa de San Antonio to Oxford?
A direct flight covers 2,241 km in about 3 h 8 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Oxford to Villa de San Antonio (reverse route)
GPS coordinates of Villa de San Antonio GPS coordinates of Oxford