Distance from Vernon to Sacaton
The distance between Vernon, Canada and Sacaton, United States is 2,008 km (1,248 miles) in a straight line. If a road route exists, expect roughly 2510 km (1560 miles) by car — around 31 h 23 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 2,008 km / 1,248 mi |
| Road distance (estimate) | ≈ 2510 km / 1560 mi |
| Driving time (estimate) | ≈ 31 h 23 min |
| Flight time (estimate) | ≈ 2 h 52 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Vernon, Canada | 50.2668671 | -119.2718157 |
| Sacaton, United States | 33.081 | -111.744578 |
Frequently asked questions
How far is Sacaton from Vernon?
The straight-line (air) distance from Vernon, Canada to Sacaton, United States is 2,008 km (1,248 miles). By road it is roughly 2510 km (1560 miles), depending on the route.
How long does it take to drive from Vernon to Sacaton?
Approximately 31 h 23 min, assuming an 80 km/h average over an estimated road distance of 2510 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Vernon to Sacaton?
A direct flight covers 2,008 km in about 2 h 52 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Sacaton to Vernon (reverse route)
GPS coordinates of Vernon GPS coordinates of Sacaton