Distance from Timmins to San Lorenzo
The distance between Timmins, Canada and San Lorenzo, United States is 3,477 km (2,160 miles) in a straight line. If a road route exists, expect roughly 4346 km (2700 miles) by car — around 54 h 20 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 3,477 km / 2,160 mi |
| Road distance (estimate) | ≈ 4346 km / 2700 mi |
| Driving time (estimate) | ≈ 54 h 20 min |
| Flight time (estimate) | ≈ 4 h 35 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Timmins, Canada | 48.476412 | -81.328925 |
| San Lorenzo, United States | 37.676616 | -122.135033 |
Frequently asked questions
How far is San Lorenzo from Timmins?
The straight-line (air) distance from Timmins, Canada to San Lorenzo, United States is 3,477 km (2,160 miles). By road it is roughly 4346 km (2700 miles), depending on the route.
How long does it take to drive from Timmins to San Lorenzo?
Approximately 54 h 20 min, assuming an 80 km/h average over an estimated road distance of 4346 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Timmins to San Lorenzo?
A direct flight covers 3,477 km in about 4 h 35 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from San Lorenzo to Timmins (reverse route)
GPS coordinates of Timmins GPS coordinates of San Lorenzo