Distance from Sedro-Woolley to Pontault-Combault

The distance between Sedro-Woolley, United States and Pontault-Combault, France is 7,971 km (4,953 miles) in a straight line. If a road route exists, expect roughly 9964 km (6191 miles) by car — around 124 h 33 min of driving.

Measure Value
Straight-line distance 7,971 km / 4,953 mi
Road distance (estimate) ≈ 9964 km / 6191 mi
Driving time (estimate) ≈ 124 h 33 min
Flight time (estimate) ≈ 9 h 53 min

Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.

Place Latitude Longitude
Sedro-Woolley, United States 48.503322 -122.235451
Pontault-Combault, France 48.801483959 2.607672064

Frequently asked questions

How far is Pontault-Combault from Sedro-Woolley?

The straight-line (air) distance from Sedro-Woolley, United States to Pontault-Combault, France is 7,971 km (4,953 miles). By road it is roughly 9964 km (6191 miles), depending on the route.

How long does it take to drive from Sedro-Woolley to Pontault-Combault?

Approximately 124 h 33 min, assuming an 80 km/h average over an estimated road distance of 9964 km. Actual time depends on the route, traffic and border crossings.

How long is the flight from Sedro-Woolley to Pontault-Combault?

A direct flight covers 7,971 km in about 9 h 53 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.

How do I calculate distances for a whole list of locations?

Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.

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