Distance from Scott County to Otse
The distance between Scott County, United States and Otse, Botswana is 14,199 km (8,823 miles) in a straight line. If a road route exists, expect roughly 17748 km (11028 miles) by car — around 221 h 51 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 14,199 km / 8,823 mi |
| Road distance (estimate) | ≈ 17748 km / 11028 mi |
| Driving time (estimate) | ≈ 221 h 51 min |
| Flight time (estimate) | ≈ 17 h 12 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Scott County, United States | 34.86064902518 | -94.063225933036 |
| Otse, Botswana | -25.0291784 | 25.745693 |
Frequently asked questions
How far is Otse from Scott County?
The straight-line (air) distance from Scott County, United States to Otse, Botswana is 14,199 km (8,823 miles). By road it is roughly 17748 km (11028 miles), depending on the route.
How long does it take to drive from Scott County to Otse?
Approximately 221 h 51 min, assuming an 80 km/h average over an estimated road distance of 17748 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Scott County to Otse?
A direct flight covers 14,199 km in about 17 h 12 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Otse to Scott County (reverse route)
GPS coordinates of Scott County GPS coordinates of Otse