Distance from Sassenheim to Montceau-les-Mines

The distance between Sassenheim, Netherlands The and Montceau-les-Mines, France is 617 km (383 miles) in a straight line. If a road route exists, expect roughly 771 km (479 miles) by car — around 9 h 38 min of driving.

Measure Value
Straight-line distance 617 km / 383 mi
Road distance (estimate) ≈ 771 km / 479 mi
Driving time (estimate) ≈ 9 h 38 min
Flight time (estimate) ≈ 1 h 14 min

Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.

Place Latitude Longitude
Sassenheim, Netherlands The 52.2153 4.5171
Montceau-les-Mines, France 46.66667 4.36667

Frequently asked questions

How far is Montceau-les-Mines from Sassenheim?

The straight-line (air) distance from Sassenheim, Netherlands The to Montceau-les-Mines, France is 617 km (383 miles). By road it is roughly 771 km (479 miles), depending on the route.

How long does it take to drive from Sassenheim to Montceau-les-Mines?

Approximately 9 h 38 min, assuming an 80 km/h average over an estimated road distance of 771 km. Actual time depends on the route, traffic and border crossings.

How long is the flight from Sassenheim to Montceau-les-Mines?

A direct flight covers 617 km in about 1 h 14 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.

How do I calculate distances for a whole list of locations?

Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.

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