Distance from San Miguel del Padrón to Bang Sue
The distance between San Miguel del Padrón, Cuba and Bang Sue, Thailand is 15,900 km (9,880 miles) in a straight line. If a road route exists, expect roughly 19875 km (12350 miles) by car — around 248 h 26 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 15,900 km / 9,880 mi |
| Road distance (estimate) | ≈ 19875 km / 12350 mi |
| Driving time (estimate) | ≈ 248 h 26 min |
| Flight time (estimate) | ≈ 19 h 12 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| San Miguel del Padrón, Cuba | 23.0935667 | -82.3301533 |
| Bang Sue, Thailand | 13.809685153 | 100.537466044 |
Frequently asked questions
How far is Bang Sue from San Miguel del Padrón?
The straight-line (air) distance from San Miguel del Padrón, Cuba to Bang Sue, Thailand is 15,900 km (9,880 miles). By road it is roughly 19875 km (12350 miles), depending on the route.
How long does it take to drive from San Miguel del Padrón to Bang Sue?
Approximately 248 h 26 min, assuming an 80 km/h average over an estimated road distance of 19875 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from San Miguel del Padrón to Bang Sue?
A direct flight covers 15,900 km in about 19 h 12 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Bang Sue to San Miguel del Padrón (reverse route)
GPS coordinates of San Miguel del Padrón GPS coordinates of Bang Sue