Distance from San Lorenzo to Angle Park
The distance between San Lorenzo, United States and Angle Park, Australia is 13,012 km (8,085 miles) in a straight line. If a road route exists, expect roughly 16265 km (10107 miles) by car — around 203 h 19 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 13,012 km / 8,085 mi |
| Road distance (estimate) | ≈ 16265 km / 10107 mi |
| Driving time (estimate) | ≈ 203 h 19 min |
| Flight time (estimate) | ≈ 15 h 49 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| San Lorenzo, United States | 37.676616 | -122.135033 |
| Angle Park, Australia | -34.85795209 | 138.559473238 |
Frequently asked questions
How far is Angle Park from San Lorenzo?
The straight-line (air) distance from San Lorenzo, United States to Angle Park, Australia is 13,012 km (8,085 miles). By road it is roughly 16265 km (10107 miles), depending on the route.
How long does it take to drive from San Lorenzo to Angle Park?
Approximately 203 h 19 min, assuming an 80 km/h average over an estimated road distance of 16265 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from San Lorenzo to Angle Park?
A direct flight covers 13,012 km in about 15 h 49 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Angle Park to San Lorenzo (reverse route)
GPS coordinates of San Lorenzo GPS coordinates of Angle Park