Distance from San José to Banovo Polje
The distance between San José, Costa Rica and Banovo Polje, Serbia is 10,271 km (6,382 miles) in a straight line. If a road route exists, expect roughly 12839 km (7978 miles) by car — around 160 h 29 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 10,271 km / 6,382 mi |
| Road distance (estimate) | ≈ 12839 km / 7978 mi |
| Driving time (estimate) | ≈ 160 h 29 min |
| Flight time (estimate) | ≈ 12 h 35 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| San José, Costa Rica | 9.9331345 | -84.0797794 |
| Banovo Polje, Serbia | 44.9092485 | 19.4461467 |
Frequently asked questions
How far is Banovo Polje from San José?
The straight-line (air) distance from San José, Costa Rica to Banovo Polje, Serbia is 10,271 km (6,382 miles). By road it is roughly 12839 km (7978 miles), depending on the route.
How long does it take to drive from San José to Banovo Polje?
Approximately 160 h 29 min, assuming an 80 km/h average over an estimated road distance of 12839 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from San José to Banovo Polje?
A direct flight covers 10,271 km in about 12 h 35 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Banovo Polje to San José (reverse route)