Distance from San Jacinto to Parc-Boutin
The distance between San Jacinto, Philippines and Parc-Boutin, Canada is 12,953 km (8,049 miles) in a straight line. If a road route exists, expect roughly 16192 km (10061 miles) by car — around 202 h 24 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 12,953 km / 8,049 mi |
| Road distance (estimate) | ≈ 16192 km / 10061 mi |
| Driving time (estimate) | ≈ 202 h 24 min |
| Flight time (estimate) | ≈ 15 h 44 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| San Jacinto, Philippines | 16.0729241 | 120.4378612 |
| Parc-Boutin, Canada | 46.552233 | -71.264728 |
Frequently asked questions
How far is Parc-Boutin from San Jacinto?
The straight-line (air) distance from San Jacinto, Philippines to Parc-Boutin, Canada is 12,953 km (8,049 miles). By road it is roughly 16192 km (10061 miles), depending on the route.
How long does it take to drive from San Jacinto to Parc-Boutin?
Approximately 202 h 24 min, assuming an 80 km/h average over an estimated road distance of 16192 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from San Jacinto to Parc-Boutin?
A direct flight covers 12,953 km in about 15 h 44 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Parc-Boutin to San Jacinto (reverse route)
GPS coordinates of San Jacinto GPS coordinates of Parc-Boutin