Distance from San Francisco to Kryspinów
The distance between San Francisco, United States and Kryspinów, Poland is 9,571 km (5,947 miles) in a straight line. If a road route exists, expect roughly 11964 km (7434 miles) by car — around 149 h 33 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 9,571 km / 5,947 mi |
| Road distance (estimate) | ≈ 11964 km / 7434 mi |
| Driving time (estimate) | ≈ 149 h 33 min |
| Flight time (estimate) | ≈ 11 h 46 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| San Francisco, United States | 37.7800771 | -122.4201615 |
| Kryspinów, Poland | 50.046089014 | 19.799023461 |
Frequently asked questions
How far is Kryspinów from San Francisco?
The straight-line (air) distance from San Francisco, United States to Kryspinów, Poland is 9,571 km (5,947 miles). By road it is roughly 11964 km (7434 miles), depending on the route.
How long does it take to drive from San Francisco to Kryspinów?
Approximately 149 h 33 min, assuming an 80 km/h average over an estimated road distance of 11964 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from San Francisco to Kryspinów?
A direct flight covers 9,571 km in about 11 h 46 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Kryspinów to San Francisco (reverse route)
GPS coordinates of San Francisco GPS coordinates of Kryspinów