Distance from Putnam to Guanabacoa
The distance between Putnam, United States and Guanabacoa, Cuba is 2,156 km (1,339 miles) in a straight line. If a road route exists, expect roughly 2695 km (1675 miles) by car — around 33 h 41 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 2,156 km / 1,339 mi |
| Road distance (estimate) | ≈ 2695 km / 1675 mi |
| Driving time (estimate) | ≈ 33 h 41 min |
| Flight time (estimate) | ≈ 3 h 2 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Putnam, United States | 42.459663 | -83.941829 |
| Guanabacoa, Cuba | 23.1208156 | -82.3053618 |
Frequently asked questions
How far is Guanabacoa from Putnam?
The straight-line (air) distance from Putnam, United States to Guanabacoa, Cuba is 2,156 km (1,339 miles). By road it is roughly 2695 km (1675 miles), depending on the route.
How long does it take to drive from Putnam to Guanabacoa?
Approximately 33 h 41 min, assuming an 80 km/h average over an estimated road distance of 2695 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Putnam to Guanabacoa?
A direct flight covers 2,156 km in about 3 h 2 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Guanabacoa to Putnam (reverse route)
GPS coordinates of Putnam GPS coordinates of Guanabacoa