Distance from Otse to Sedro-Woolley

The distance between Otse, Botswana and Sedro-Woolley, United States is 16,199 km (10,066 miles) in a straight line. If a road route exists, expect roughly 20249 km (12582 miles) by car — around 253 h 7 min of driving.

Measure Value
Straight-line distance 16,199 km / 10,066 mi
Road distance (estimate) ≈ 20249 km / 12582 mi
Driving time (estimate) ≈ 253 h 7 min
Flight time (estimate) ≈ 19 h 33 min

Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.

Place Latitude Longitude
Otse, Botswana -25.0291784 25.745693
Sedro-Woolley, United States 48.503322 -122.235451

Frequently asked questions

How far is Sedro-Woolley from Otse?

The straight-line (air) distance from Otse, Botswana to Sedro-Woolley, United States is 16,199 km (10,066 miles). By road it is roughly 20249 km (12582 miles), depending on the route.

How long does it take to drive from Otse to Sedro-Woolley?

Approximately 253 h 7 min, assuming an 80 km/h average over an estimated road distance of 20249 km. Actual time depends on the route, traffic and border crossings.

How long is the flight from Otse to Sedro-Woolley?

A direct flight covers 16,199 km in about 19 h 33 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.

How do I calculate distances for a whole list of locations?

Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.

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