Distance from Oildale to Banovo Polje
The distance between Oildale, United States and Banovo Polje, Serbia is 10,153 km (6,309 miles) in a straight line. If a road route exists, expect roughly 12692 km (7886 miles) by car — around 158 h 39 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 10,153 km / 6,309 mi |
| Road distance (estimate) | ≈ 12692 km / 7886 mi |
| Driving time (estimate) | ≈ 158 h 39 min |
| Flight time (estimate) | ≈ 12 h 27 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Oildale, United States | 35.4196027 | -119.0212761 |
| Banovo Polje, Serbia | 44.9092485 | 19.4461467 |
Frequently asked questions
How far is Banovo Polje from Oildale?
The straight-line (air) distance from Oildale, United States to Banovo Polje, Serbia is 10,153 km (6,309 miles). By road it is roughly 12692 km (7886 miles), depending on the route.
How long does it take to drive from Oildale to Banovo Polje?
Approximately 158 h 39 min, assuming an 80 km/h average over an estimated road distance of 12692 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Oildale to Banovo Polje?
A direct flight covers 10,153 km in about 12 h 27 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Banovo Polje to Oildale (reverse route)
GPS coordinates of Oildale GPS coordinates of Banovo Polje