Distance from Montpezat-de-Quercy to Banovo Polje
The distance between Montpezat-de-Quercy, France and Banovo Polje, Serbia is 1,422 km (884 miles) in a straight line. If a road route exists, expect roughly 1778 km (1105 miles) by car — around 22 h 14 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 1,422 km / 884 mi |
| Road distance (estimate) | ≈ 1778 km / 1105 mi |
| Driving time (estimate) | ≈ 22 h 14 min |
| Flight time (estimate) | ≈ 2 h 10 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Montpezat-de-Quercy, France | 44.237434979 | 1.476960903 |
| Banovo Polje, Serbia | 44.9092485 | 19.4461467 |
Frequently asked questions
How far is Banovo Polje from Montpezat-de-Quercy?
The straight-line (air) distance from Montpezat-de-Quercy, France to Banovo Polje, Serbia is 1,422 km (884 miles). By road it is roughly 1778 km (1105 miles), depending on the route.
How long does it take to drive from Montpezat-de-Quercy to Banovo Polje?
Approximately 22 h 14 min, assuming an 80 km/h average over an estimated road distance of 1778 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Montpezat-de-Quercy to Banovo Polje?
A direct flight covers 1,422 km in about 2 h 10 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Banovo Polje to Montpezat-de-Quercy (reverse route)
GPS coordinates of Montpezat-de-Quercy GPS coordinates of Banovo Polje