Distance from Minalin to Guanabacoa
The distance between Minalin, Philippines and Guanabacoa, Cuba is 15,093 km (9,379 miles) in a straight line. If a road route exists, expect roughly 18867 km (11723 miles) by car — around 235 h 50 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 15,093 km / 9,379 mi |
| Road distance (estimate) | ≈ 18867 km / 11723 mi |
| Driving time (estimate) | ≈ 235 h 50 min |
| Flight time (estimate) | ≈ 18 h 15 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Minalin, Philippines | 14.971215 | 120.7345361 |
| Guanabacoa, Cuba | 23.1208156 | -82.3053618 |
Frequently asked questions
How far is Guanabacoa from Minalin?
The straight-line (air) distance from Minalin, Philippines to Guanabacoa, Cuba is 15,093 km (9,379 miles). By road it is roughly 18867 km (11723 miles), depending on the route.
How long does it take to drive from Minalin to Guanabacoa?
Approximately 235 h 50 min, assuming an 80 km/h average over an estimated road distance of 18867 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Minalin to Guanabacoa?
A direct flight covers 15,093 km in about 18 h 15 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Guanabacoa to Minalin (reverse route)
GPS coordinates of Minalin GPS coordinates of Guanabacoa