Distance from Market Lavington to Ozark
The distance between Market Lavington, United Kingdom and Ozark, United States is 6,968 km (4,330 miles) in a straight line. If a road route exists, expect roughly 8711 km (5413 miles) by car — around 108 h 53 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 6,968 km / 4,330 mi |
| Road distance (estimate) | ≈ 8711 km / 5413 mi |
| Driving time (estimate) | ≈ 108 h 53 min |
| Flight time (estimate) | ≈ 8 h 42 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Market Lavington, United Kingdom | 51.28643553 | -1.979222325 |
| Ozark, United States | 37.025476 | -93.211075 |
Frequently asked questions
How far is Ozark from Market Lavington?
The straight-line (air) distance from Market Lavington, United Kingdom to Ozark, United States is 6,968 km (4,330 miles). By road it is roughly 8711 km (5413 miles), depending on the route.
How long does it take to drive from Market Lavington to Ozark?
Approximately 108 h 53 min, assuming an 80 km/h average over an estimated road distance of 8711 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Market Lavington to Ozark?
A direct flight covers 6,968 km in about 8 h 42 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Ozark to Market Lavington (reverse route)
GPS coordinates of Market Lavington GPS coordinates of Ozark