Distance from Lüchow to Poppenbüttel
The distance between Lüchow, Germany and Poppenbüttel, Germany is 105 km (65 miles) in a straight line. If a road route exists, expect roughly 131 km (81 miles) by car — around 1 h 38 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 105 km / 65 mi |
| Road distance (estimate) | ≈ 131 km / 81 mi |
| Driving time (estimate) | ≈ 1 h 38 min |
| Flight time (estimate) | ≈ 37 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Lüchow, Germany | 52.967742999 | 11.161706 |
| Poppenbüttel, Germany | 53.65917 | 10.08472 |
Frequently asked questions
How far is Poppenbüttel from Lüchow?
The straight-line (air) distance from Lüchow, Germany to Poppenbüttel, Germany is 105 km (65 miles). By road it is roughly 131 km (81 miles), depending on the route.
How long does it take to drive from Lüchow to Poppenbüttel?
Approximately 1 h 38 min, assuming an 80 km/h average over an estimated road distance of 131 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Lüchow to Poppenbüttel?
A direct flight covers 105 km in about 37 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Poppenbüttel to Lüchow (reverse route)
GPS coordinates of Lüchow GPS coordinates of Poppenbüttel