Distance from Johannesburg to Buckeye
The distance between Johannesburg, South Africa and Buckeye, United States is 16,156 km (10,039 miles) in a straight line. If a road route exists, expect roughly 20196 km (12549 miles) by car — around 252 h 27 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 16,156 km / 10,039 mi |
| Road distance (estimate) | ≈ 20196 km / 12549 mi |
| Driving time (estimate) | ≈ 252 h 27 min |
| Flight time (estimate) | ≈ 19 h 30 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Johannesburg, South Africa | -26.201452 | 28.045488 |
| Buckeye, United States | 33.370497 | -112.583575 |
Frequently asked questions
How far is Buckeye from Johannesburg?
The straight-line (air) distance from Johannesburg, South Africa to Buckeye, United States is 16,156 km (10,039 miles). By road it is roughly 20196 km (12549 miles), depending on the route.
How long does it take to drive from Johannesburg to Buckeye?
Approximately 252 h 27 min, assuming an 80 km/h average over an estimated road distance of 20196 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Johannesburg to Buckeye?
A direct flight covers 16,156 km in about 19 h 30 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Buckeye to Johannesburg (reverse route)