Distance from Jeff Davis County to San José del Potrero
The distance between Jeff Davis County, United States and San José del Potrero, Honduras is 1,945 km (1,208 miles) in a straight line. If a road route exists, expect roughly 2431 km (1511 miles) by car — around 30 h 23 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 1,945 km / 1,208 mi |
| Road distance (estimate) | ≈ 2431 km / 1511 mi |
| Driving time (estimate) | ≈ 30 h 23 min |
| Flight time (estimate) | ≈ 2 h 47 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Jeff Davis County, United States | 31.805531639609 | -82.63688534813 |
| San José del Potrero, Honduras | 14.83963 | -87.28485 |
Frequently asked questions
How far is San José del Potrero from Jeff Davis County?
The straight-line (air) distance from Jeff Davis County, United States to San José del Potrero, Honduras is 1,945 km (1,208 miles). By road it is roughly 2431 km (1511 miles), depending on the route.
How long does it take to drive from Jeff Davis County to San José del Potrero?
Approximately 30 h 23 min, assuming an 80 km/h average over an estimated road distance of 2431 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Jeff Davis County to San José del Potrero?
A direct flight covers 1,945 km in about 2 h 47 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from San José del Potrero to Jeff Davis County (reverse route)
GPS coordinates of Jeff Davis County GPS coordinates of San José del Potrero