Distance from Hietzing to Banovo Polje
The distance between Hietzing, Austria and Banovo Polje, Serbia is 437 km (271 miles) in a straight line. If a road route exists, expect roughly 546 km (339 miles) by car — around 6 h 50 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 437 km / 271 mi |
| Road distance (estimate) | ≈ 546 km / 339 mi |
| Driving time (estimate) | ≈ 6 h 50 min |
| Flight time (estimate) | ≈ 1 h 1 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Hietzing, Austria | 48.18623 | 16.2965 |
| Banovo Polje, Serbia | 44.9092485 | 19.4461467 |
Frequently asked questions
How far is Banovo Polje from Hietzing?
The straight-line (air) distance from Hietzing, Austria to Banovo Polje, Serbia is 437 km (271 miles). By road it is roughly 546 km (339 miles), depending on the route.
How long does it take to drive from Hietzing to Banovo Polje?
Approximately 6 h 50 min, assuming an 80 km/h average over an estimated road distance of 546 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Hietzing to Banovo Polje?
A direct flight covers 437 km in about 1 h 1 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Banovo Polje to Hietzing (reverse route)
GPS coordinates of Hietzing GPS coordinates of Banovo Polje