Distance from D'Aguilar Town/ Rennock Lodge to Austin
The distance between D'Aguilar Town/ Rennock Lodge, Jamaica and Austin, United States is 2,526 km (1,569 miles) in a straight line. If a road route exists, expect roughly 3157 km (1962 miles) by car — around 39 h 28 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 2,526 km / 1,569 mi |
| Road distance (estimate) | ≈ 3157 km / 1962 mi |
| Driving time (estimate) | ≈ 39 h 28 min |
| Flight time (estimate) | ≈ 3 h 28 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| D'Aguilar Town/ Rennock Lodge, Jamaica | 17.97001 | -76.73701 |
| Austin, United States | 30.264979 | -97.746598 |
Frequently asked questions
How far is Austin from D'Aguilar Town/ Rennock Lodge?
The straight-line (air) distance from D'Aguilar Town/ Rennock Lodge, Jamaica to Austin, United States is 2,526 km (1,569 miles). By road it is roughly 3157 km (1962 miles), depending on the route.
How long does it take to drive from D'Aguilar Town/ Rennock Lodge to Austin?
Approximately 39 h 28 min, assuming an 80 km/h average over an estimated road distance of 3157 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from D'Aguilar Town/ Rennock Lodge to Austin?
A direct flight covers 2,526 km in about 3 h 28 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Austin to D'Aguilar Town/ Rennock Lodge (reverse route)
GPS coordinates of D'Aguilar Town/ Rennock Lodge GPS coordinates of Austin