Distance from Caledon to Banovo Polje
The distance between Caledon, South Africa and Banovo Polje, Serbia is 8,801 km (5,469 miles) in a straight line. If a road route exists, expect roughly 11001 km (6836 miles) by car — around 137 h 31 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 8,801 km / 5,469 mi |
| Road distance (estimate) | ≈ 11001 km / 6836 mi |
| Driving time (estimate) | ≈ 137 h 31 min |
| Flight time (estimate) | ≈ 10 h 51 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Caledon, South Africa | -34.239474480662 | 19.427578757781 |
| Banovo Polje, Serbia | 44.9092485 | 19.4461467 |
Frequently asked questions
How far is Banovo Polje from Caledon?
The straight-line (air) distance from Caledon, South Africa to Banovo Polje, Serbia is 8,801 km (5,469 miles). By road it is roughly 11001 km (6836 miles), depending on the route.
How long does it take to drive from Caledon to Banovo Polje?
Approximately 137 h 31 min, assuming an 80 km/h average over an estimated road distance of 11001 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Caledon to Banovo Polje?
A direct flight covers 8,801 km in about 10 h 51 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Banovo Polje to Caledon (reverse route)
GPS coordinates of Caledon GPS coordinates of Banovo Polje