Distance from Buckow to Lilienthal
The distance between Buckow, Germany and Lilienthal, Germany is 353 km (219 miles) in a straight line. If a road route exists, expect roughly 441 km (274 miles) by car — around 5 h 31 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 353 km / 219 mi |
| Road distance (estimate) | ≈ 441 km / 274 mi |
| Driving time (estimate) | ≈ 5 h 31 min |
| Flight time (estimate) | ≈ 55 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Buckow, Germany | 52.568175 | 14.073102001 |
| Lilienthal, Germany | 53.141291999 | 8.907720001 |
Frequently asked questions
How far is Lilienthal from Buckow?
The straight-line (air) distance from Buckow, Germany to Lilienthal, Germany is 353 km (219 miles). By road it is roughly 441 km (274 miles), depending on the route.
How long does it take to drive from Buckow to Lilienthal?
Approximately 5 h 31 min, assuming an 80 km/h average over an estimated road distance of 441 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Buckow to Lilienthal?
A direct flight covers 353 km in about 55 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Lilienthal to Buckow (reverse route)
GPS coordinates of Buckow GPS coordinates of Lilienthal