Distance from Banovo Polje to New York City
The distance between Banovo Polje, Serbia and New York City, United States is 7,189 km (4,467 miles) in a straight line. If a road route exists, expect roughly 8986 km (5584 miles) by car — around 112 h 20 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 7,189 km / 4,467 mi |
| Road distance (estimate) | ≈ 8986 km / 5584 mi |
| Driving time (estimate) | ≈ 112 h 20 min |
| Flight time (estimate) | ≈ 8 h 57 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Banovo Polje, Serbia | 44.9092485 | 19.4461467 |
| New York City, United States | 40.7130466 | -74.0072301 |
Frequently asked questions
How far is New York City from Banovo Polje?
The straight-line (air) distance from Banovo Polje, Serbia to New York City, United States is 7,189 km (4,467 miles). By road it is roughly 8986 km (5584 miles), depending on the route.
How long does it take to drive from Banovo Polje to New York City?
Approximately 112 h 20 min, assuming an 80 km/h average over an estimated road distance of 8986 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Banovo Polje to New York City?
A direct flight covers 7,189 km in about 8 h 57 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from New York City to Banovo Polje (reverse route)
GPS coordinates of Banovo Polje GPS coordinates of New York City