Distance from Bang Phlat to Boyeros
The distance between Bang Phlat, Thailand and Boyeros, Cuba is 15,915 km (9,889 miles) in a straight line. If a road route exists, expect roughly 19893 km (12361 miles) by car — around 248 h 40 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 15,915 km / 9,889 mi |
| Road distance (estimate) | ≈ 19893 km / 12361 mi |
| Driving time (estimate) | ≈ 248 h 40 min |
| Flight time (estimate) | ≈ 19 h 13 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Bang Phlat, Thailand | 13.794065578 | 100.504921201 |
| Boyeros, Cuba | 22.9723461 | -82.3839652 |
Frequently asked questions
How far is Boyeros from Bang Phlat?
The straight-line (air) distance from Bang Phlat, Thailand to Boyeros, Cuba is 15,915 km (9,889 miles). By road it is roughly 19893 km (12361 miles), depending on the route.
How long does it take to drive from Bang Phlat to Boyeros?
Approximately 248 h 40 min, assuming an 80 km/h average over an estimated road distance of 19893 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Bang Phlat to Boyeros?
A direct flight covers 15,915 km in about 19 h 13 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Boyeros to Bang Phlat (reverse route)
GPS coordinates of Bang Phlat GPS coordinates of Boyeros